Adv
AnilSinghBora
  • 0
Guru

CD and GH are respectively the bisectors of ∠ACB and ∠EGF such that D and H lie on sides AB and FE of ΔABC and ΔEFG respectively. If ΔABC ~ ΔFEG, Show that: (i) CD/GH = AC/FG Q10.(1)

  • 0

How i solve this tough question in easy way of chapter triangles of class 10th of exercise 6.3 of class 10th math, please help me to find out the solution of this question  CD and GH are respectively the bisectors of ∠ACB and ∠EGF such that D and H lie on sides AB and FE of ΔABC and ΔEFG respectively. If ΔABC ~ ΔFEG, Show that: (i) CD/GH = AC/FG

Share

1 Answer

  1. Ncert solutions class 10 chapter 6-20

    (i) From the given condition,

    ΔABC ~ ΔFEG.

    ∴ ∠A = ∠F, ∠B = ∠E, and ∠ACB = ∠FGE

    Since, ∠ACB = ∠FGE

    ∴ ∠ACD = ∠FGH (Angle bisector)

    And, ∠DCB = ∠HGE (Angle bisector)

    In ΔACD and ΔFGH,

    ∠A = ∠F

    ∠ACD = ∠FGH

    ∴ ΔACD ~ ΔFGH (AA similarity criterion)

    ⇒CD/GH = AC/FG

    • 0
Leave an answer

Leave an answer

Browse

Choose from here the video type.

Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

Captcha Click on image to update the captcha.

Related Questions