Find this important question of ncert class 9th of chapter triangles .Sir please help me to find out the easiest and simplest solution of question 4 of exercise 7.3, give me the best solution of this question. BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles.
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BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles. Q.4
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Solution:
It is known that BE and CF are two equal altitudes.
Now, in ΔBEC and ΔCFB,
BEC = CFB = 90° (Same Altitudes)
BC = CB (Common side)
BE = CF (Common side)
So, ΔBEC ΔCFB by RHS congruence criterion.
Also, C = B (by CPCT)
Therefore, AB = AC as sides opposite to the equal angles is always equal.