0 Deepak Bora Asked: August 31, 20202020-08-31T09:51:57+05:30 2020-08-31T09:51:57+05:30In: CBSE, Competition, ICSE, IIT Argument of a Complex Number 0 Why does the Principal Argument of any Complex Number lie between -π to π. ? Isn’t that the Equivalent of saying 0 to 2π ? algebra (kinda)complex numbersprincipal argument Share Facebook Related Questions Question 20. In the given figure, tangents PQ and PR are drawn from an external point P to ... Question 19. In the given figure, AD is a diameter of a circle with centre O and AB ... Question 18. (a) In the figure (i) given below, PA and PB are tangents at a points A ... Question 17. Two circles with centres A, B are of radii 6 cm and 3 cm respectively. If ... Question 16. In the given figure, AC is a transverse common tangent to two circles with centres P ... 1 Answer Voted Oldest Recent Deepak Bora 2020-08-31T12:38:54+05:30Added an answer on August 31, 2020 at 12:38 pm Hello AshwinBabu, You asked a great question about the argument of a complex number. The principal argument of a complex number is from -π to π as you said. Itcan also be said that it’s equivalent to having it from 0 to 2π. Actually sin (3π) will also give the same values as sin (π) and sin (2π). So we can write it that way. But to avoid confusion, we take only one rotation (and by default we say its from -π to π). It’s just a way of saying something… I hope it’s clear. If not, you can WhatsApp truemaths at 8477885599. Or post another question on this portal. 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment.