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An observer 1.5 m tall is 20.5 metres away from a tower 22 metres high. Determine the angle of elevation of the top of the tower from the eye of the observer.

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sir this is the question from the book -ML aggarwal( avichal publication) class 10th , chapter20 , heights and distances. IT’s very important question we have   been given that An observer 1.5 m tall is 20.5 metres away from a tower 22 metres high.
we are asked to Determine the angle of elevation of the top of the tower from the eye of the observer.

question no 13 , heights and distances , ICSE board

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1 Answer

  1. In the figure,

    AB is the tower and CD is an observer

    θ is the angle of observation

    ML Aggarwal Solutions for Class 10 Chapter 20 Image 13

    It is given that

    AB = 22m

    CD = 1.5 m

    Distance BD = 20.5 m

    From the point C construct CE parallel tp DB

    AE = 22 – 1.5 = 20.5 m

    CE = DB = 20.5 m

    tan θ = AE/CE

    Substituting the values

    tan θ = 20.5/20.5 = 1

    tan 450 = 1

    θ = 450

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