How i solve the question of quadratic equations of exercise 4.3 of question no,10. I am not able to solve this question so please help me for solving this question. An express train takes 1 hour less than a passenger train to travel 132 km between Mysore and Bangalore (without taking into consideration the time they stop at intermediate stations). If the average speeds of the express train is 11 km/h more than that of the passenger train, find the average speed of the two trains.

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# An express train takes 1 hour less than a passenger train to travel 132 km between Mysore and Bangalore (without taking into consideration the time they stop at intermediate stations). If the average speeds of the express train is 11 km/h more than that of the passenger train, find the average speed of the two trains. Q.10

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Let us say, the average speed of passenger train = Â

xÂ km/h.Average speed of express train = (

xÂ + 11) km/hGiven, time taken by the express train to cover 132 km is 1 hour less than the passenger train to cover the same distance. Therefore,

(132/x) â€“ (132/(x+11)) = 1

132(x+11-x)/(x(x+11)) = 1

132 Ã— 11 /(x(x+11)) = 1

â‡’ 132 Ã— 11 =Â

x(xÂ + 11)â‡’Â

x^{2}Â + 11xÂ â€“ 1452 = 0â‡’Â

x^{2}Â +Â 44xÂ -33xÂ -1452 = 0â‡’Â

x(xÂ + 44) -33(xÂ + 44) = 0â‡’ (

xÂ + 44)(xÂ â€“ 33) = 0â‡’Â

xÂ = â€“ 44, 33As we know, Speed cannot be negative.

Therefore, the speed of the passenger train will be 33 km/h and thus, the speed of the express train will be 33 + 11 = 44 km/h.