Deepak Bora
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Amit, standing on a horizontal plane, finds a bird flying at a distance of 200 m from him at an elevation of 30°. Deepak standing on the roof of a 50 m high building, finds the angle of elevation of the same bird to be 45°. Amit and Deepak are on opposite sides of the bird. Find the distance of the bird from Deepak.

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CBSE 10th Class past year question paper

Year 2019

SET 1, Code Number- 30/2/1

Question number – 24

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1 Answer

  1. In ∆APQ
    PQ/AP = sin 30º = 1/2

    PQ = (200)(1/2)

    = 100 m

    PR = 100 – 50

    PR = 50 m

    In ∆PRD,
    PR/PD = sin 45° = 1/√2
    PD = (PR)( √2)

    = 50 √2 m

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