How can i solve this tough question of class 9^{th} ncert of Areas of Parallelograms and Triangles of math of exercise 9.3 of question no.12 . Give me the best and simple way for solving this question. A villager Itwaari has a plot of land of the shape of a quadrilateral. The Gram Panchayat of the village decided to take over some portion of his plot from one of the corners to construct a Health Centre. Itwaari agrees to the above proposal with the condition that he should be given equal amount of land in lieu of his land adjoining his plot so as to form a triangular plot. Explain how this proposal will be implemented.

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# A villager Itwaari has a plot of land of the shape of a quadrilateral. The Gram Panchayat of the village decided to take over some portion of his plot from one of the corners to construct a Health Centre. Itwaari agrees to the above proposal with the condition that he should be given equal amount of land in lieu of his land adjoining his plot so as to form a triangular plot. Explain how this proposal will be implemented. Q.12

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Let ABCD be the plot of the land of the shape of a quadrilateral.

To Construct,

Join the diagonal BD.

Draw AE parallel to BD.

Join BE, that intersected AD at O.

We get,

â–³BCE is the shape of the original field

â–³AOB is the area for constructing health centre.

â–³DEO is the land joined to the plot.

To prove:

ar(â–³DEO) = ar(â–³AOB)

Proof:

â–³DEB and â–³DAB lie on the same base BD, in-between the same parallels BD and AE.

Ar(â–³DEB) = ar(â–³DAB)

â‡’ar(â–³DEB) â€“ arâ–³DOB) = ar(â–³DAB) â€“ ar(â–³DOB)

â‡’Â ar(â–³DEO) = ar(â–³AOB)