This is the Important question of class 10 Based on Mensuration Chapter of M.L Aggarwal book for ICSE BOARD.

The radius of a solid metallic hemisphere is given, it is melted and recasted into right circular cone of base radius 6 cm. Find the height of the cone.

This is the Question Number 03, Exercise 17.5 of M.L Aggarwal.

Deepak BoraNewbie

# A solid metallic hemisphere of radius 8 cm is melted and recasted into right circular cone of base radius 6 cm. Determine the height of the cone.

Share

Given radius of the hemisphere, r = 8 cmVolume of the hemisphere, V = (2/3)r^{3}= (2/3)×8^{3}= (1024/3) cm^{3}Radius of cone, R = 6 cmSince hemisphere is melted and recasted into a cone, the volume remains the same.Volume of the cone, (1/3)R^{2}h = (1024/3)(1/3)×6^{2 }×h = (1024/3)36h = 1024

h = 1024/36

= 28.44 cm

Hence the height of the cone is 28.44 cm.