This is the Important question of class 10 Based on Mensuration Chapter of M.L Aggarwal book for ICSE BOARD.

A soft drink is available in two packs (i) a tin can with a rectangular base its length and width is given, having a height and (ii) a plastic cylinder with circular base of diameter and height is given. Which container has greater capacity and by how much?

This is the Question Number 21, Exercise 17.1 of M.L Aggarwal.

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# A soft drink is available in two packs (i) a tin can with a rectangular base of length 5 cm and width 4 cm, having a height of 15 cm and (ii) a plastic cylinder with circular base of diameter 7 cm and height 10 cm. Which container has greater capacity and by how much?

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(i) Length of the can,l= 5 cmWidth, b = 4 cmHeight, h = 15 cmVolume of the can =lbh= 5×4×15= 300 cm^{3}(ii) Diameter of the cylinder, d = 7 cmRadius, r = d/2 = 7/2 = 3.5 cmHeight, h = 10 cmVolume of the cylinder, V = r^{2}h= (22/7)×3.5^{2}×10= 385 cm^{3}Difference of the volume = 385-300 = 85 cm^{3}Hence the plastic cylinder has 85 cm^{3 }more volume than the tin can.