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Deepak Bora
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A road roller (in the shape of a cylinder) has a diameter 0.7 m and its width is 1.2 m. Find the least number of revolutions that the roller must make in order to level a playground of size 120 m by 44 m.

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An Important Question of M.L Aggarwal book of class 10 Based on Mensuration Chapter for ICSE BOARD.
A road roller (in the shape of a cylinder) having diameterand and its width.
Find the least number of revolutions that the roller must make in order to level a playground of given size in question. Give the solution of the question briefly.
This is the Question Number 06, Exercise 17.1 of M.L Aggarwal.

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1 Answer

  1. Given diameter of the road roller, d = 0.7 m

    Radius, r = d/2 = 0.7/2 = 0.35 m

    Width, h = 1.2 m

    Curved surface area of the road roller = 2rh

    =2 ×(22/7)×0.35×1.2

    = 2.64 m2

    Area of the play ground = l×b

    120×44

    = 5280 m2

    Number of revolutions = Area of play ground / Curved surface area

    = 5280/2.64

    = 2000

    Hence the road roller must take 2000 revolutions to level the ground.

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