M.L Aggarwal book Important Question of class 10 chapter Based on Mensuration for ICSE BOARD.

A right triangle with sides given is revolved about a side .

Find the volume and the curved surface of the cone so formed

This is the Question Number 17, Exercise 17.2 of M.L Aggarwal.

Deepak BoraNewbie

# A right triangle with sides 6 cm, 8 cm and 10 cm is revolved about the side 8 cm. Find the volume and the curved surface of the cone so formed. (Take pi = 3.14)

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The triangle is rotated about the side 8cm.So the height of the resulting cone, h = 8 cmRadius, r = 6 cmSlant height,l =10 cmVolume of the cone, V = (1/3)r^{2}hV = (1/3)×3.14×6^{2}×8V = (1/3)×3.14×36×8V = 3.14×12×8V = 301.44 cm^{3}Hence the volume of the cone is 301.44 cm^{3}.Curved surface area of the cone = rl= 3.14×6×10= 188.4Hence the curved surface area of the cone is 188.4 cm^{2}.