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AnilSinghBora
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A hemispherical bowl made of brass has inner diameter 10.5cm. Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm2. (Assume π = 22/7) Q.5

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  1. Inner radius of hemispherical bowl, say r = diameter/2 = (10.5)/2 cm = 5.25 cm

    Formula for Surface area of hemispherical bowl = 2πr2

    = 2×(22/7)×(5.25)2 = 173.25

    Surface area of hemispherical bowl is 173.25 cm2

    Cost of tin-plating 100 cm2 area = Rs 16

    Cost of tin-plating 1 cm2 area = Rs 16 /100

    Cost of tin-plating 173.25 cm2 area = Rs. (16×173.25)/100 = Rs 27.72

    Therefore, the cost of tin-plating the inner side of the hemispherical bowl at the rate of Rs 16 per 100 cm2 is Rs 27.72.

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