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A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5cm. Find the outer curved surface of the bowl. (Assume π =22/7) Q.8

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I don’t know how to solve this problem of Surface Areas and Volumes of exercise 13.4  of class 9th math give me the easiest and simple way for solving this tough question of question no.8 A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5cm. Find the outer curved surface of the bowl. (Assume π =22/7)

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1 Answer

  1. Given:

    Inner radius of hemispherical bowl = 5cm

    Thickness of the bowl = 0.25 cm

    Outer radius of hemispherical bowl = (5+0.25) cm = 5.25 cm

    Formula for outer CSA of hemispherical bowl = 2πr2, where r is radius of hemisphere

    = 2×(22/7)×(5.25)2 = 173.25

    Therefore, the outer curved surface area of the bowl is 173.25 cm2.

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