What are the different way for solving the question for class 9th question of Surface Areas and Volumes chapter of math of question no.8 of math please suggest me the best way for solving this question of exercise 13.8 A dome of a building is in the form of a hemi sphere. From inside, it was white-washed at the cost of Rs. 4989.60. If the cost of white-washing isRs20 per square meter, find the (i) inside surface area of the dome (ii) volume of the air inside the dome (Assume π = 22/7)
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A dome of a building is in the form of a hemi sphere. From inside, it was white-washed at the cost of Rs. 4989.60. If the cost of white-washing isRs20 per square meter, find the (i) inside surface area of the dome (ii) volume of the air inside the dome (Assume π = 22/7) Q.8
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(i) Cost of white-washing the dome from inside = Rs 4989.60
Cost of white-washing 1m2 area = Rs 20
CSA of the inner side of dome = 498.96/2 m2 = 249.48 m2
(ii) Let the inner radius of the hemispherical dome be r.
CSA of inner side of dome = 249.48 m2 (from (i))
Formula to find CSA of a hemi sphere = 2πr2
2πr2 = 249.48
2×(22/7)×r2 = 249.48
r2 = (249.48×7)/(2×22)
r2 = 39.69
r = 6.3
So, radius is 6.3 m
Volume of air inside the dome = Volume of hemispherical dome
Using formula, volume of the hemisphere = 2/3 πr3
= (2/3)×(22/7)×6.3×6.3×6.3
= 523.908
= 523.9(approx.)
Answer: Volume of air inside the dome is 523.9 m3.