An Important Question of M.L Aggarwal book of class 10 Based on Mensuration Chapter for ICSE BOARD.

A cylindrical tube open at both ends is made of metal. The internal diameter and length of the tube is given .

And the metal thickness is also given. Calculate the volume of the metal.

This is the Question Number 18, Exercise 17.1 of M.L Aggarwal.

Deepak BoraNewbie

# A cylindrical tube open at both ends is made of metal. The internal diameter of the tube is 11.2 cm and its length is 21 cm. The metal thickness is 0.4 cm. Calculate the volume of the metal.

Share

Given internal diameter of the tube = 11.2 cmInternal radius, r = d/2 = 11.2/2 = 5.6 cmLength of the tube, h = 21 cmThickness = 0.4 cmOuter radius, R= 5.6+0.4 = 6 cmVolume of the metal = R^{2}h- r^{2}h= h(R^{2}-r^{2})= (22/7)×21×(6^{2}-5.6^{2})= 66×(6+5.6)(6-5.6)= 66×11.6×0.4= 306.24 cm^{3}Hence the volume of the metal is 306.24 cm^{3}.