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A cylindrical tube open at both ends is made of metal. The internal diameter of the tube is 11.2 cm and its length is 21 cm. The metal thickness is 0.4 cm. Calculate the volume of the metal.

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An Important Question of M.L Aggarwal book of class 10 Based on Mensuration Chapter for ICSE BOARD.
A cylindrical tube open at both ends is made of metal. The internal diameter and length of the tube is given .
And the metal thickness is also given. Calculate the volume of the metal.
This is the Question Number 18, Exercise 17.1 of M.L Aggarwal.

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1 Answer

  1. Given internal diameter of the tube = 11.2 cm

    Internal radius, r = d/2 = 11.2/2 = 5.6 cm

    Length of the tube, h = 21 cm

    Thickness = 0.4 cm

    Outer radius, R= 5.6+0.4 = 6 cm

    Volume of the metal = R2h- r2h

    = h(R2-r2)

    = (22/7)×21×(62-5.62)

    = 66×(6+5.6)(6-5.6)

    = 66×11.6×0.4

    = 306.24 cm3

    Hence the volume of the metal is 306.24 cm3.

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