What is the best solution of the question from the applications of Trigonometry of ncert of exercise 9.1 of class 10th math please give me the best solution for this question A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 30°.
Length of the rope is 20 m and angle made by the rope with the ground level is 30°.
Given: AC = 20 m and angle C = 30°
To Find: Height of the pole
Let AB be the vertical pole
In right ΔABC, using sine formula
sin 30° = AB/AC
Using value of sin 30 degrees is ½, we have
1/2 = AB/20
AB = 20/2
AB = 10
Therefore, the height of the pole is 10 m.