What is the best solution of the question of class 10th ncert math of Probability chapter of exercise 15.1 of question no.19 give me the best and the simple way for solving this chapter A child has a die whose six faces show the letters as given below:
The total number of possible outcomes (or events) = 6
P(E) = (Number of favourable outcomes/ Total number of outcomes)
(i) The total number of faces having A on it = 2
P (getting A) = 2/6 = ⅓ = 0.33
(ii) The total number of faces having D on it = 1
P (getting D) = ⅙ = 0.166