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Deepak Bora
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A chemist has one solution containing 50% acid and a second one containtng 25% acid. How much of each should be used to make 10 litres of a 40% acid solution?

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An Important question based on Linear Equations in two Variables Chapter of R.S Aggarwal book for ICSE &
CBSE Board.
Here Given :
(i)Chemist solutions containing acid in percentage
You have to find how much of each should be used to make 10 litres of a 40% acid solution.
This is the Question Number 53 Exercise 3E of RS Aggarwal Solution.

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1 Answer

  1. Let the amount of 50% acid be x liters.
    And the amount of 25% acid be y litres.
    To make 10 litres of 40% acid solution,
    0.5x+0.25y=4———-(i)
    x+y=10————–(ii)
    [balancing concentrations]
    Multiply the equation (i) by 10.
    Then the equation (i) becomes,
    (i)x10=5x+2.5y=40———-(iii)
    And multiply the equation (ii) by 5
    Then the equation (ii) becomes,
    (ii)x5=5x+5y=50———(iv)
    By subtracting, equation (iii) from (iv)
    Subtracting,
    5x+2.5y=40
    5x+5y=50
    -2.5y=-10
    Then,
    y=10/2.5=4
    Substituting the value of y, (y = 4) in equation (iii) we get,
    5x+2.5y=40
    5x+2.5(4)=40
    5x+10=40
    5x=30
    x=6
    Hence, 6 litres of 50% solution and 4 litres of 25% solution are needed to form 10 litres of 40% of acid solutions.

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