Adv
Rajan@2021
  • 0
Guru

A chemist has one solution containing 50% acid and a second one containing 25% acid. How much of each should be mixed to make 10 litres of a 40% acid solution.

  • 0

An important and exam oriented question from linear equations in two variables in which we have given that a chemist has one solution containing 50% acid and a second one containing 25% acid. We have been asked to find how much of each should be mixed to make 10 litres of a 40% acid solution.

Kindly give me a detailed solution of this question

RS Aggarwal, Class 10, chapter 3E, question no 49

Share

1 Answer

  1. Let X be the amount of first solution and Y be the amount of second to be taken.

    The amount of acid in x=0.5x

    But another 50% has to be water.

    The amount of water =0.5x.

    The amount of acid in y=0.25y

    The amount of water in y=0.75y

    The total amount of acid required in final solution =0.4×10=4 litres and remaining 6 lit would be water.

    Therefore,

    0.5x+0.25y=4 ………….(1)

    Or,0.5x=4−0.25y

    Similarly for water,

    0.5x+0.75y=6  ……………..(2)

    Substituting the value of 0.5x from Eq. (1) into Eq. (2) we have,

    4−0.25y+0.75y=6

    4+0.5y=6

    y=4

    x=6

    • 0
Leave an answer

Leave an answer

Browse

Choose from here the video type.

Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

Captcha Click on image to update the captcha.

Related Questions