Explain, how did we split the number in the equation.
How to prove?
Class 10th, Statistics, Rd sharma, Mathematics.
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2. In each of the following, determine whether the given values are solutions of the given equation or not: (v) 2×2 – x + 9 = x2 + 4x + 3, x = 2, x = 3
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Solution:
Here we have,
2x2 – x + 9 = x2 + 4x + 3
⇒ x2 – 5x + 6 = 0
LHS = x2 – 5x + 6
Substituting x = 2 in LHS, we get
(2)2 – 5(2) + 6
⇒ 4 – 10 + 6 = 0 = RHS
⇒ LHS = RHS
Thus, x = 2 is a solution to the given equation.
Similarly,
Substituting x = 3 in LHS, we get
(3)2 – 5(3) + 6
⇒ 9 – 15 + 6 = 0 = RHS
⇒ LHS = RHS
Thus, x = 3 is a solution to the given equation.