Explain, how did we split the number in the equation.
How to prove?
Class 10th, Statistics, Rd sharma, Mathematics.
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2. In each of the following, determine whether the given values are solutions of the given equation or not: (i) x2 – 3x + 2 = 0 , x = 2 , x = – 1
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Solution:
Here we have,
LHS = x2 – 3x + 2
Substituting x = 2 in LHS, we get
(2)2 – 3(2) + 2
⇒ 4 – 6 + 2 = 0 = RHS
⇒ LHS = RHS
Thus, x = 2 is a solution of the given equation.
Similarly,
Substituting x = -1 in LHS, we get
(-1)2 – 3(-1) + 2
⇒ 1 + 3 + 2 = 6 ≠ RHS
⇒ LHS ≠ RHS
Thus, x = -1 is not a solution to the given equation.