How do you evolve this sum using the trigonometric formulas.
Class 10th, Rd sharma, Trigonometric identities.
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Solution:
(i) We have,
sin 20o/ cos 70o = sin (90o – 70o)/ cos 70o = cos 70o/ cos70o = 1 [∵ sin (90 – θ) = cos θ]
(ii) We have,
cos 19o/ sin 71o = cos (90o – 71o)/ sin 71o = sin 71o/ sin 71o = 1 [∵ cos (90 – θ) = sin θ]