pair of linear equations in two variables ncert Archives - Page 5 of 6

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AnilSinghBoraGuru

Asked: July 14, 2021In: NCERT Class 10th Maths

Solve the following pair of linear equations by the elimination method and the substitution method:(ii) 3x + 4y = 10 and 2x – 2y = 2 Q.1(2)

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By both elimination method and substitution method how i solve this question Solve the following pair of linear equations by ...Read more

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AnilSinghBoraGuru

Asked: July 14, 2021In: NCERT Class 10th Maths

Solve the following pair of linear equations by the elimination method and the substitution method: (i) x + y = 5 and 2x – 3y = 4 Q.1(1)

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I want the solution of this question of both 2 method of elimination and the substitution method. Please help me ...Read more

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AnilSinghBoraGuru

Asked: July 14, 2021In: NCERT Class 10th Maths

Form the pair of linear equations for the following problems and find their solution by substitution method.(vi) Five years hence, the age of Jacob will be three times that of his son. Five years ago, Jacob’s age was seven times that of his son. What are their present ages? Q.3(6)

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This is one of the most important type of question of class 10th math of Chapter Pair of linear equations ...Read more

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AnilSinghBoraGuru

Asked: July 14, 2021In: NCERT Class 10th Maths

Form the pair of linear equations for the following problems and find their solution by substitution method.A fraction becomes 9/11 , if 2 is added to both the numerator and the denominator. If, 3 is added to both the numerator and the denominator it becomes 5/6. Find the fraction. Q.3(5)

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Yesterday i am doing this question but it looking tough for me to solve this question how can i easily ...Read more

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AnilSinghBoraGuru

Asked: July 14, 2021In: NCERT Class 10th Maths

Form the pair of linear equations for the following problems and find their solution by substitution method.(iv) The taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km, the charge paid is Rs 105 and for a journey of 15 km, the charge paid is Rs 155. What are the fixed charges and the charge per km? How much does a person have to pay for travelling a distance of 25 km? Q.3(4)

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I am not able to solve this question how can i easily solve the question of Pair of Linear Equations ...Read more

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AnilSinghBoraGuru

Asked: July 14, 2021In: NCERT Class 10th Maths

Form the pair of linear equations for the following problems and find their solution by substitution method.(iii) The coach of a cricket team buys 7 bats and 6 balls for Rs.3800. Later, she buys 3 bats and 5 balls for Rs.1750. Find the cost of each bat and each ball. Q.3(3)

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The third part of class10 math of exercise 3.3 i don’t know how to solve this question by easy way ...Read more

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AnilSinghBoraGuru

Asked: July 14, 2021In: NCERT Class 10th Maths

Form the pair of linear equations for the following problems and find their solution by substitution method.(ii) The larger of two supplementary angles exceeds the smaller by 18 degrees. Find them. Q.3(2)

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The best question of class 10th math. How i solve this question it is important regarding to board exam Form ...Read more

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AnilSinghBoraGuru

Asked: July 14, 2021In: NCERT Class 10th Maths

Form the pair of linear equations for the following problems and find their solution by substitution method. (i) The difference between two numbers is 26 and one number is three times the other. Find them. Q.3(1)

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The question no.3 of part 1 of exercise 3.3 of math of 10th class how i solve this question. I ...Read more

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AnilSinghBoraGuru

Asked: July 14, 2021In: NCERT Class 10th Maths

Solve 2x + 3y = 11 and 2x – 4y = – 24 and hence find the value of ‘m’ for which y = mx + 3. Q.2

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How i solve Solve 2x + 3y = 11 and 2x – 4y = – 24 and hence find the ...Read more

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AnilSinghBoraGuru

Asked: July 14, 2021In: NCERT Class 10th Maths

1. Solve the following pair of linear equations by the substitution method (i) x + y = 14 x – y = 4 (ii) s – t = 3 (s/3) + (t/2) = 6 (iii) 3x – y = 3 9x – 3y = 9 (iv) 0.2x + 0.3y = 1.3 0.4x + 0.5y = 2.3 (v) √2 x+√3 y = 0 √3 x-√8 y = 0 (vi) (3x/2) – (5y/3) = -2 (x/3) + (y/2) = (13/6) Q.1

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The question of linear equations how can i solve this question by substitution method. I think it is also the ...Read more

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