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## Nazima is fly fishing in a stream. The tip of her fishing rod is 1.8 m above the surface of the water and the fly at the end of the string rests on the water 3.6 m away and 2.4 m from a point directly under the tip of the rod. Assuming that her string (from the tip of her rod to the fly) is taut, how much string does she have out (see Figure)? If she pulls in the string at the rate of 5 cm per second, what will be the horizontal distance of the fly from her after 12 seconds? Q.10

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How i solve this problem in easy way of Triangles chapter of exercise 6.6 of ncert math of last question ...Read more

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## In Figure, D is a point on side BC of ∆ ABC such that BD/CD = AB/AC. Prove that AD is the bisector of ∠ BAC. Q.9

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Hello, sir give me the best way to solve the problem of Triangles chapter of class 10th of exercise 6.6 ...Read more

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## In Fig. 6.62, two chords AB and CD of a circle intersect each other at the point P (when produced) outside the circle. Prove that: (i) ∆ PAC ~ ∆ PDB (ii) PA . PB = PC . PD.Q.8

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How i solve this question of Triangles chapter of exercise 6.6 of ncert math of question no.8 give me the ...Read more

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## In Figure, two chords AB and CD intersect each other at the point P. Prove that : (i) ∆APC ~ ∆ DPB (ii) AP . PB = CP . DP Q.7

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Please give me the best way to solve the problem of Class 10th math of ncert of triangles chapter of ...Read more

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## Prove that the sum of the squares of the diagonals of parallelogram is equal to the sum of the squares of its sides. Q.6

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The best question of optional chapter of class 10th math of chapter name Triangles of exercise 6.6, Give me the ...Read more

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## In Figure, AD is a median of a triangle ABC and AM ⊥ BC. Prove that : (iii) AC2 + AB2 = 2 AD2 + ½ BC2 Q.5(3)

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In the class 10th maths book in triangles chapter of exercise 6.6 of ncert how i solve this problem in ...Read more

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## In Figure, AD is a median of a triangle ABC and AM ⊥ BC. Prove that : (ii) AB2 = AD2 – BC.DM + 2 (BC/2) 2 Q.5(2)

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How i solve this problem of class 10th of ncert math of exercise 6.6 of question no5(2). What is the ...Read more

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## In Figure, AD is a median of a triangle ABC and AM ⊥ BC. Prove that : (i) AC2 = AD2 + BC.DM + 2 (BC/2) 2 Q.5(1)

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How i solve this question of class 10th math of exercise 6.6 of Triangles chapter , Please suggest me the ...Read more

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## In Figure, ABC is a triangle in which ∠ ABC < 90° and AD ⊥ BC. Prove that AC2= AB2+ BC2 – 2 BC.BD. Q.4

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For class 10 Triangles chapter of exercise 6.6 of ncert math, how i solve this chapter because it is an ...Read more

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## In Figure, ABC is a triangle in which ∠ABC > 90° and AD ⊥ CB produced. Prove that AC2= AB2+ BC2+ 2 BC.BD. Q.3

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The important question of class 10th ncert book of exercise 6.6 of triangles chapter , What is the best way ...Read more