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deepaksoniGuru

Asked: March 15, 2021In: ICSE

(i) (1 + sin A)/ cos A + cos A/ (1 + sin A) = 2 sec A (ii) tan A/ (sec A – 1) + tan A/ (sec A + 1) = 2cosec A

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This is an important question taken from the Book Book- ML Aggarwal Board- ICSE Publication- Avichal Chapter- Trigonometric Identities Chapter ...Read more

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deepaksoniGuru

Asked: March 15, 2021In: ICSE

(i) (sec A – 1)/(sec A + 1) = (1 – cos A)/(1 + cos A) (ii) tan2 θ/ (sec θ – 1)2 = (1 + cos θ)/ (1 – cos θ) (iii) (1 + tan A)2 + (1 – tan A)2 = 2 sec2 A (iv) sec2 A + cosec2 A = sec2 A. cosec2 A

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This question has been taken from the Book- ML Aggarwal Board- ICSE Publication- Avichal Chapter- Trigonometric Identities Chapter number-18 We ...Read more

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deepaksoniGuru

Asked: March 15, 2021In: ICSE

(i) sin A/ (1 + cos A) = (1 – cos A)/ sin A (ii) (1 – tan2 A)/ (cot2 A – 1) = tan2 A (iii) sin A/ (1 + cos A) = cosec A – cot A

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This is an important question taken from the Book ML Aggarwal, Avichal publication, class 10th and, chapter 18 We have to ...Read more

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deepaksoniGuru

Asked: March 15, 2021In: ICSE

(i) 1/ (1 + cos A) + 1/ (1 – cos A) = 2 cosec2 A (ii) 1/(sec A + tan A) + 1/(sec A – tan A) = 2 sec A

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This question has been taken form the Book- ML Aggarwal Board- ICSE Publication- Avichal Chapter- Trigonometric Identities Chapter number-18 We have to ...Read more

0

deepaksoniGuru

Asked: March 15, 2021In: ICSE

(i) tan A + cot A = sec A cosec A (ii) (1 – cos A) (1 + sec A) = tan A sin A

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This ques has been taken from Book- ML Aggarwal Board- ICSE Publication- Avichal Chapter- Trigonometric Identities Chapter number-18 We hage have to ...Read more

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deepaksoniGuru

Asked: March 15, 2021In: ICSE

(i) (sec A + tan A) (1 – sin A) = cos A (ii) (1 + tan2 A) (1 – sin A) (1 + sin A) = 1

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This is an important question taken from the Book- ML Aggarwal Board- ICSE Publication- Avichal Chapter- Trigonometric Identities Chapter number-1 We ...Read more

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deepaksoniGuru

Asked: March 15, 2021In: ICSE

Prove that following: (i) cos θ sin (90° – θ) + sin θ cos (90° – θ) = 1 (ii) tan θ/ tan (90o – θ) + sin (90o – θ)/ cos θ = sec2 θ (iii) (cos (90o – θ) cos θ)/ tan θ + cos2 (90o – θ) = 1 (iv) sin (90o – θ) cos (90o – θ) = tan θ/ (1 + tan2 θ)

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This ques is very important and has been taken from the Book- ML Aggarwal Board- ICSE Publication- Avichal Chapter- Trigonometric IdentitiesRead more

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(i) (1 + sin A)/ cos A + cos A/ (1 + sin A) = 2 sec A (ii) tan A/ (sec A – 1) + tan A/ (sec A + 1) = 2cosec A

(i) (sec A – 1)/(sec A + 1) = (1 – cos A)/(1 + cos A) (ii) tan2 θ/ (sec θ – 1)2 = (1 + cos θ)/ (1 – cos θ) (iii) (1 + tan A)2 + (1 – tan A)2 = 2 sec2 A (iv) sec2 A + cosec2 A = sec2 A. cosec2 A

(i) sin A/ (1 + cos A) = (1 – cos A)/ sin A (ii) (1 – tan2 A)/ (cot2 A – 1) = tan2 A (iii) sin A/ (1 + cos A) = cosec A – cot A

(i) 1/ (1 + cos A) + 1/ (1 – cos A) = 2 cosec2 A (ii) 1/(sec A + tan A) + 1/(sec A – tan A) = 2 sec A

(i) tan A + cot A = sec A cosec A (ii) (1 – cos A) (1 + sec A) = tan A sin A

(i) (sec A + tan A) (1 – sin A) = cos A (ii) (1 + tan2 A) (1 – sin A) (1 + sin A) = 1

Prove that following: (i) cos θ sin (90° – θ) + sin θ cos (90° – θ) = 1 (ii) tan θ/ tan (90o – θ) + sin (90o – θ)/ cos θ = sec2 θ (iii) (cos (90o – θ) cos θ)/ tan θ + cos2 (90o – θ) = 1 (iv) sin (90o – θ) cos (90o – θ) = tan θ/ (1 + tan2 θ)