Home - Ask TrueMaths!

0

deepaksoniGuru

Asked: March 16, 2021In: ICSE

(i) Root{(secA-1) /(secA+1)} + Root{(secA+1) /(secA-1) = 2cosecA (ii) cos A cot A/ (1 – sin A) = 1 + cosec A

0

This is an important question from the Book- ML Aggarwal Board- ICSE Publication- Avichal Chapter- Trigonometric Identities Chapter number-18 We have ...Read more

0

deepaksoniGuru

Asked: March 16, 2021In: ICSE

(i) Root{(1+sinA)/(1-sinA)}= tanA+secA (ii) root{(1-cosA)/(1+cosA)}= cosecA-cotA

0

This is an important question from the Book- ML Aggarwal Board- ICSE Publication- Avichal Chapter- Trigonometric Identities Chapter number-18 We have ...Read more

0

deepaksoniGuru

Asked: March 16, 2021In: ICSE

(i) (1 + cosec A)/ cosec A = cos2 A/ (1 – sin A) (ii) root{(1-cosA/(1+cosA)} =sinA/(1+cosA)

0

This question has been taken from the Book- ML Aggarwal Board- ICSE Publication- Avichal Chapter- Trigonometric Identities Chapter number-18 (i) (1 + cosec A)/ cosec ...Read more

0

deepaksoniGuru

Asked: March 16, 2021In: ICSE

(i) (1+cos theta -sin^2 theta) / sin theta (1 + cos theta ) = cot theta. (ii)tan³ A – 1 / tan A -1 = sec² A + tan A

0

This ques has been taken from the Book Book- ML Aggarwal Board- ICSE Publication- Avichal Chapter- Trigonometric Identities Chapter number-18Read more

1

deepaksoniGuru

Asked: March 15, 2021In: ICSE

(i) cosec4 θ – cosec2 θ = cot4 θ + cot2 θ (ii) 2 sec2 θ – sec4 θ – 2 cosec2 θ + cosec4 θ = cot4 θ – tan4 θ.

1

This is an important question taken from the Book Book- ML Aggarwal Board- ICSE Publication- Avichal Chapter- Trigonometric Identities Chapter number-18Read more

0

deepaksoniGuru

Asked: March 15, 2021In: ICSE

(i) tan2 θ – sin2 θ = tan2 θ sin2 θ (ii) cos θ/ (1 – tan θ) – sin2 θ/ (cos θ – sin θ) = cos θ + sin θ

0

This is an important question taken from the Book Book- ML Aggarwal Board- ICSE Publication- Avichal Chapter- Trigonometric Identities Chapter ...Read more

0

deepaksoniGuru

Asked: March 15, 2021In: ICSE

(i) cosec A/ (cosec A – 1) + cosec A/ (cosec A + 1) = 2 sec2 A (ii) cot A – tan A = (2cos2 A – 1)/ (sin A – cos A) (iii) (cot A – 1)/ (2 – sec2 A) = cot A/ (1 + tan A)

0

This ques has been asked in previous year question paper of class 10 and is the very important ques from ...Read more

Share & grow the world's knowledge!

Discy Latest Questions

(i) Root{(secA-1) /(secA+1)} + Root{(secA+1) /(secA-1) = 2cosecA (ii) cos A cot A/ (1 – sin A) = 1 + cosec A

(i) Root{(1+sinA)/(1-sinA)}= tanA+secA (ii) root{(1-cosA)/(1+cosA)}= cosecA-cotA

(i) (1 + cosec A)/ cosec A = cos2 A/ (1 – sin A) (ii) root{(1-cosA/(1+cosA)} =sinA/(1+cosA)

(i) (1+cos theta -sin^2 theta) / sin theta (1 + cos theta ) = cot theta. (ii)tan³ A – 1 / tan A -1 = sec² A + tan A

(i) cosec4 θ – cosec2 θ = cot4 θ + cot2 θ (ii) 2 sec2 θ – sec4 θ – 2 cosec2 θ + cosec4 θ = cot4 θ – tan4 θ.

(i) tan2 θ – sin2 θ = tan2 θ sin2 θ (ii) cos θ/ (1 – tan θ) – sin2 θ/ (cos θ – sin θ) = cos θ + sin θ

(i) cosec A/ (cosec A – 1) + cosec A/ (cosec A + 1) = 2 sec2 A (ii) cot A – tan A = (2cos2 A – 1)/ (sin A – cos A) (iii) (cot A – 1)/ (2 – sec2 A) = cot A/ (1 + tan A)