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Rajan@2021Guru

Asked: March 25, 2021In: ICSE

In the adjoining figure, medians AD and BE of △ABC meet at the point G, and DF is drawn parallel to BE. Prove that (i) EF=FC (ii) AG:GD=2:1.

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In the figure we have been asked to Prove that (i) EF=FC (ii) AG:GD=2:1. If Medians AD and BE intersect each ...Read more

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Rajan@2021Guru

Asked: March 25, 2021In: ICSE

In the given figure, CM and RN are respectively the medians of △ABC and △PQR. If △ABC∼△PQR, prove that: (i) △AMC∼△PQR (ii) CM/RN=AB/PQ (iii) △CMB∼△RNQ.

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An important question from similarity chapter in which we are asked to prove (i) △AMC∼△PQR (ii) CM/RN=AB/PQ (iii) △CMB∼△RNQ. If the given triangles are ...Read more

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Rajan@2021Guru

Asked: March 25, 2021In: ICSE

The altitudes BN and CM of ΔABC meet at H. Prove that (1) CN.HM=BM.HN (2) HB HC = BM.HM CN.HN (3)ΔMHN∼ΔBHC

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In the given question we are asked to prove (1) CN.HM=BM.HN (2) HB HC = BM.HM CN.HN (3)ΔMHN∼ΔBHC ML Aggarwal Avichal ...Read more

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Rajan@2021Guru

Asked: March 25, 2021In: ICSE

In the figure given below PQRS is a parallelogram; PQ =16 cm , QR = 10 cm . L is a point on PR such that RL: LP = 2: 3.QL produced meets RS at M and PS produced at N. i) prove that triangle RLQ is similar to triangle PLN.hence , find PN. ii) name a triangle similar to triangle RLM. evaluate RM.

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One of the most important question of Similarities in which we have been asked to i) prove that triangle RLQ is ...Read more

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Rajan@2021Guru

Asked: March 25, 2021In: ICSE

In the figure given below, E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that △ABE∼△CFB.

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I came across a question from similarity chapter in which I found difficulty in solving the problem in which we ...Read more

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Rajan@2021Guru

Asked: March 25, 2021In: ICSE

In the given figure, DB⊥BC, DE⊥AB and AC⊥BC. Prove that BE/DE = AC/BC

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In this given question we have to prove that the ratio of two sides of triangle are equal if DB⊥BC, ...Read more

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Rajan@2021Guru

Asked: March 25, 2021In: ICSE

In △ABC,∠A is acute. BD and CE are perpendicular on AC and AB respectively. Prove that AB×AE=AC×AD.

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One of the basic question from similarity chapter in which we have been asked to prove that ratio of two ...Read more

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In the adjoining figure, medians AD and BE of △ABC meet at the point G, and DF is drawn parallel to BE. Prove that (i) EF=FC (ii) AG:GD=2:1.

In the given figure, CM and RN are respectively the medians of △ABC and △PQR. If △ABC∼△PQR, prove that: (i) △AMC∼△PQR (ii) CM/RN=AB/PQ (iii) △CMB∼△RNQ.

The altitudes BN and CM of ΔABC meet at H. Prove that (1) CN.HM=BM.HN (2) HB HC ​ = BM.HM CN.HN ​ ​ (3)ΔMHN∼ΔBHC

In the figure given below PQRS is a parallelogram; PQ =16 cm , QR = 10 cm . L is a point on PR such that RL: LP = 2: 3.QL produced meets RS at M and PS produced at N. i) prove that triangle RLQ is similar to triangle PLN.hence , find PN. ii) name a triangle similar to triangle RLM. evaluate RM.

In the figure given below, E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that △ABE∼△CFB.

In the given figure, DB⊥BC, DE⊥AB and AC⊥BC. Prove that BE/DE = AC/BC

In △ABC,∠A is acute. BD and CE are perpendicular on AC and AB respectively. Prove that AB×AE=AC×AD.

The altitudes BN and CM of ΔABC meet at H. Prove that (1) CN.HM=BM.HN (2) HB HC = BM.HM CN.HN (3)ΔMHN∼ΔBHC