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mehakNewbie

Asked: June 17, 2023In: CBSE

In each of the following systems of equations, determine whether the system has a unique solution, no solution or infinite solutions. In case there is a unique solution, find it from 1 to 4. 1. x − 3y = 3 3x − 9y = 2

Explain the unique solution,no solution or infinite solutions Class 10th rd sharma pair of linear equations in two variables.

mehakNewbie

Asked: July 21, 2023In: CBSE

1. Find the distance between the following pair of points. (i) (- 6, 7) and (-1, -5) (ii) (a + b, b + c) and (a -b, c – b) (iii) (a sin α, – b cos α) and (- a cos α, b sin α)

Explain this question of coordinate geometry using various formulas, stated in the Rd sharma book. Class 10th Cbse, Rd Sharma, Coordinate Geometry.

deepaksoniGuru

Asked: March 10, 2021In: ICSE

What sum should a person invest in Rs 25 shares, selling at Rs 36, obtain an income of Rs 720, if the dividend declared is 12%? Also find the percentage return on his income.

sir this is a question from the book -ML aggarwal( avichal publication)class 10th , chapter3, shares and dividends Kindly solve this ...Read more

deepaksoniGuru

Asked: March 11, 2021In: ICSE

A ladder is placed against a wall such that it reaches the top of the wall. The foot of the ladder is 1.5 metres away from the wall and the ladder is inclined at an angle of 600 with the ground. Find the height of the wall.

sir this is the question from the book -ML aggarwal( avichal publication) class 10th , chapter20 , heights and distancesRead more

deepaksoniGuru

Asked: March 11, 2021In: ICSE

A vertical pole and a vertical tower are on the same level ground. From the top of the pole the angle of elevation of the top of the tower is 60 and the angle of depression of the foot of the tower is 30. Find the height of the tower if the height of the pole is 20 m.

sir this is the important question from the book -ML aggarwal( avichal publication) class 10th , chapter20 , heights and ...Read more

deepaksoniGuru

Asked: March 16, 2021In: ICSE

(i) 1/ (sec A + tan A) – 1/cos A = 1/cos A – 1/(sec A – tan A) (ii) (sin A + sec A)2 + (cos A + cosec A)2 = (1 + sec A cosec A)2 (iii) (tan A + sin A)/ (tan A – sin A) = (sec A + 1)/ (sec A – 1)

This is an important question from the Book- ML Aggarwal Board- ICSE Publication- Avichal Chapter- Trigonometric Identities Chapter number-18 We. Have ...Read more

deepaksoniGuru

Asked: March 16, 2021In: ICSE

The perimeter of a rectangular plot is 180 m and its area is 1800 m². Take the length of the plot as x m. Use the perimeter 180 m to write the value of the breadth in terms of x. Use the values of length, breadth and the area to write an equation in x. Solve the equation to calculate the length and breadth of the plot.

This question has been taken from Book:- ML aggarwal, Avichal publication, class10th, quadratic equation in one variable, chapter 5, exercise ...Read more

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Discy Latest Questions

In each of the following systems of equations, determine whether the system has a unique solution, no solution or infinite solutions. In case there is a unique solution, find it from 1 to 4. 1. x − 3y = 3 3x − 9y = 2

1. Find the distance between the following pair of points. (i) (- 6, 7) and (-1, -5) (ii) (a + b, b + c) and (a -b, c – b) (iii) (a sin α, – b cos α) and (- a cos α, b sin α)

What sum should a person invest in Rs 25 shares, selling at Rs 36, obtain an income of Rs 720, if the dividend declared is 12%? Also find the percentage return on his income.

A ladder is placed against a wall such that it reaches the top of the wall. The foot of the ladder is 1.5 metres away from the wall and the ladder is inclined at an angle of 600 with the ground. Find the height of the wall.

A vertical pole and a vertical tower are on the same level ground. From the top of the pole the angle of elevation of the top of the tower is 60 and the angle of depression of the foot of the tower is 30. Find the height of the tower if the height of the pole is 20 m.

(i) 1/ (sec A + tan A) – 1/cos A = 1/cos A – 1/(sec A – tan A) (ii) (sin A + sec A)2 + (cos A + cosec A)2 = (1 + sec A cosec A)2 (iii) (tan A + sin A)/ (tan A – sin A) = (sec A + 1)/ (sec A – 1)