Please help me to find out the best solution of ncert class 10 of the chapter introduction of trigonometry. Give me the best solution of the exercise 8.3 of question 2(1) .How i solve this question quickly and easily. Show that: (i) tan 48° tan 23° tan 42° tan 67° = 1.
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tan 48° tan 23° tan 42° tan 67°
Simplify the given problem by converting some of the tan functions to the cot functions
We know that, tan 48° = tan (90° – 42°) = cot 42°
tan 23° = tan (90° – 67°) = cot 67°
= tan (90° – 42°) tan (90° – 67°) tan 42° tan 67°
Substitute the values
= cot 42° cot 67° tan 42° tan 67°
= (cot 42° tan 42°) (cot 67° tan 67°) = 1×1 = 1