One of the most important and exam oriented question from trigonometric identities in which we have been asked to find the value of sin48°sec42° + cos48°cosec42° by using the properties of trigonometric identities
RS Aggarwal, Class 10, chapter 13C, question no 33
We have,
cos(90−θ)=sinθ, sin(90−θ)=cosθ
∴sin48°/cos(90-48)° + cos48°/sin(90-48)°
=sin48°/sin48°+cos48°/cos48°
=1+1
=2