This question is from trigonometry topic- trigonometric ratios on complementary angles in which we have to find the value of A, if sec2A=cosec(A-42°)
RS Aggarwal, Class 10, chapter 12, question no 11.
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sec2A=csc(A−42∘)
csc(90−2A)=csc(A−42∘)
90−2A=A−42
3A=132
A=44∘