This question is from trigonometry topic- trigonometric ratios on complementary angles in which we have to express the following in terms of T-ratios of angles lying between 0° and 45°:
sin67° + cos75°
BOOK- RS Aggarwal, Class 10, chapter 12, question no 8(i)
sin67o+cos75o
=sin(90−25)°+cos(90−15)° [cos(90−θ)=sinθ,sin(90−θ)=cosθ]
=cos23°+sin15°