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Rajan@2021
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Express the following in terms of T-ratios of angles lying between 0° and 45°: sin67° + cos75°

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This question is from trigonometry topic- trigonometric ratios on complementary angles in which we have to express the following in terms of T-ratios of angles lying between 0° and 45°:

sin67° + cos75°

BOOK- RS Aggarwal, Class 10, chapter 12, question no 8(i)

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1 Answer

  1. sin67o+cos75o

    =sin(9025+cos(9015    [cos(90θ)=sinθ,sin(90θ)=cosθ]

    =cos2+sin1

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