One of the most important question of factorisation in which we have been asked to find the reminder by dividing from given polynomial f(x) = 3x^3-7x^2+4x+11
ML Aggarwal Avichal Publication Factorisation Chapter 6, question no 3(ii)
Rajan@2021Guru
Find the remainder (without division) on dividing f(x) by(2x + 1 ) where .. f(x) = 3x^3-7x^2+4x+11
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Let us assume 2x+1=0
⇒2x=−1
⇒x=−1/2
By using remainder theorem, When f(x) is divided by (2x+1),
Remainder r=f(−1/2)
=3×(−1/2)3−7×(−1/2)2+4×(−1/2)+11
=−3/8 –7/4−2+11
=− 3/8 -7/4+9
=(−3−14+72)/8
=55/8
hence the remainder is 55/8