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Find the remainder (without division) on dividing f(x) by(2x + 1 ) where .. f(x) = 3x^3-7x^2+4x+11

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One of the most important question of factorisation in which we have been asked to find the reminder by dividing from given polynomial f(x) = 3x^3-7x^2+4x+11

ML Aggarwal Avichal Publication Factorisation Chapter 6, question no 3(ii)


1 Answer

  1. Let us assume 2x+1=0
    ​By using remainder theorem, When f(x) is divided by (2x+1),
    Remainder r=f(−1/2)
    =−3/8 –7/4−2+11
    =− 3/8 -7/4+9

    hence the remainder is 55/8

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