What is the solution of the question of class 10th ncert book of Probability chapter of optional exercise 15.2 of question no.2, give me the best solution for this chapter A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is double that of a red ball, determine the number of blue balls in the bag.
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A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is double that of a red ball, determine the number of blue balls in the bag. Q.3
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It is given that the total number of red balls = 5
Let the total number of blue balls = x
So, the total no. of balls = x+5
P(E) = (Number of favourable outcomes/ Total number of outcomes)
∴ P (drawing a blue ball) = [x/(x+5)] ——–(i)
Similarly,
P (drawing a red ball) = [5/(x+5)] ——–(i)
From equation (i) and (ii)
x = 10
So, the total number of blue balls = 10