In this Question you have to find the next term of the given AP.
This is the Important question based on Arithmetic progression Chapter of R.S Aggarwal book for ICSE & CBSE
Board.
This is the Question Number 8 Of Exercise 11 D of RS Aggarwal Solution.
Deepak BoraNewbie
Write the next term of the AP √8,√18,√32,……..
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√8=√4×2=2√2
√18=√9×2=3√2
√32=√16×2=4√2
therefore next term will be,
5√2=√25×2=√50
and next root is
6√2=√36×2=√72
it continues till infinity
I will say u how I had done this method
see this is A.P
just take first term
√8 u take it and divide this √8
see properly
√(4×2)=√8
u can do like this
so, here
√4x√2=√8
u can take like also write
so now the
2x√2
therefore √4= 2
so u got this as 2√2=√8
so take next term
and try to do in these methods only so u can get it
and this is arithmetic progression so now u have to find next term
2√2,3√2,4√2,…
so there is a common difference
d=a2-a1
d=√2
so,
and next term will be 5√2