How i solve the problem of Polynomials chapter of exercise 2.5 of class 9th ncert math. I don’t know how to solve it please guide me the best way for solving it give me the best way for solving this problem Write the following cubes in expanded form:(iii) ((3/2)x+1)3
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Using identity,(x+y)3 = x3+y3+3xy(x+y)
((3/2)x+1)3=((3/2)x)3+13+(3×(3/2)x×1)((3/2)x +1)