This is the basic and conceptual question from trigonometric ratios on complementary angles in which we have to prove that tan 71° – cot 19° = 0 without using trigonometric tables
RS Aggarwal, Class 10, chapter 12, question no 2(ii).
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LHS=tan71°−cot19°
=tan(90°−19°)−cot19°
=cot19°−cot19°
=0=RHS