This is the basic and conceptual question from trigonometric ratios on complementary angles in which we have been asked to show that
cosec 80° – sec 10° = 0
RS Aggarwal, Class 10, chapter 12, question no 2(iii).
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LHS=cosec80°−sec10°
=cosec(90°−80°)−sec10°
=sec10°−sec10°
=0=RHS