This is the basic and conceptual question from trigonometric ratios in which we have to find cosec 42°/sec 48° without using trigonometric tables,
RS Aggarwal, Class 10, chapter 12, question no 1(v).
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cosec42°/sec48°
=1/sin42°/1/cos48°
=cos48°/sin(90°-48°)
=cos48°/cos48°
=1