What is the easiest way for solving the question of class 9th ncert math of exercise 2.5 of math of Polynomials chapter of question no. 16(2) Please help me for the best suggestion of this question What are the possible expressions for the dimensions of the cuboids whose volumes are given below? (ii) Volume : 12ky2+8ky–20k
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What are the possible expressions for the dimensions of the cuboids whose volumes are given below? (ii) Volume : 12ky2+8ky–20k Q.16(2)
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Volume:
12ky2+8ky–20k
12ky2+8ky–20k can be written as 4k(3y2+2y–5) by taking 4k out of both the terms.
12ky2+8ky–20k = 4k(3y2+2y–5)
[Here, 3y2+2y–5 can be written as 3y2+5y–3y–5 using splitting the middle term method.]
= 4k(3y2+5y–3y–5)
= 4k[y(3y+5)–1(3y+5)]
= 4k(3y+5)(y–1)
Possible expression for length = 4k
Possible expression for breadth = (3y +5)
Possible expression for height = (y -1)