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Verify that: x3+y3+z3–3xyz = (1/2) (x+y+z)[(x–y)2+(y–z)2+(z–x)2] Q.12

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Please guide me the best way for solving the question of class 9th math of Polynomials chapter of exercise 2.5 of math of question no. 12 What is the best way for solving this question, please guide me Verify that: x3+y3+z3–3xyz = (1/2) (x+y+z)[(x–y)2+(y–z)2+(z–x)2]

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1 Answer

  1. We know that,

    x3+y3+z3−3xyz = (x+y+z)(x2+y2+z2–xy–yz–xz)

    ⇒ x3+y3+z3–3xyz = (1/2)(x+y+z)[2(x2+y2+z2–xy–yz–xz)]

    = (1/2)(x+y+z)(2x2+2y2+2z2–2xy–2yz–2xz)

    = (1/2)(x+y+z)[(x2+y2−2xy)+(y2+z2–2yz)+(x2+z2–2xz)]

    = (1/2)(x+y+z)[(x–y)2+(y–z)2+(z–x)2]

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