An important question from factorisation in which we are to find the value of k if on dividing 2x3+3x2−kx+5 by x−2, leaves a remainder 7 using remainder theorem.
Book – ML Aggarwal, Avichal Publication Factorisation, Question no 5
Rajan@2021Guru
Using remainder theorem, find the value of k if on dividing 2x 3 +3x 2 −kx+5 by x−2, leaves a remainder 7
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x−2=0,⇒x=2
the remainder =f(2)
=2(2)3+3(2)2−k(2)+5
=16+12−2k+5
=33−2k
According to question
33−2k=7
⇒2k=26
⇒k=13