Give me the best way for solving the question of class 9th of Surface areas and Volumes of exercise 13.1 of math. Give me the easiest way for solving this question in simple way of question no.3 The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four walls at the rate of Rs.10 per m2 is Rs.15000, find the height of the hall. [Hint: Area of the four walls = Lateral surface area.]
AnilSinghBoraGuru
The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four walls at the rate of Rs.10 per m2 is Rs.15000, find the height of the hall. [Hint: Area of the four walls = Lateral surface area.] Q.3
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Let length, breadth, and height of the rectangular hall be l, b, and h respectively.
Area of four walls = 2lh+2bh
= 2(l+b)h
Perimeter of the floor of hall = 2(l+b)
= 250 m
Area of four walls = 2(l+b) h = 250h m2
Cost of painting per square meter area = Rs.10
Cost of painting 250h square meter area = Rs (250h×10) = Rs.2500h
However, it is given that the cost of paining the walls is Rs. 15000.
15000 = 2500h
Or h = 6
Therefore, the height of the hall is 6 m.