One of the most important and conceptual question from quadratic equation chapter as it was already asked in various important examinations in which we have given an equation 6x²+x-12=0 and we have been asked to solve the given equation.
Kindly give me a detailed solution of this question
RS Aggarwal, Class 10, chapter 4A, question no 14
6x²+x−12=0
6x²+9x−8x−12=0
3x(2x+3)−4(2x+3)=0
(2x+3)(3x−4)=0
Either 2x+3=0, then 2x=−3⇒x=−3/2
or 3x−4=0, then 3x=4⇒x=4/3
x=−3/2 or 4/3