I came across a difficult question from linear equations in two variables in which we have been asked to find the value of variables x and y from the equation 6x+5y=7x+3y+1=2(x+6y-1)
Kindly solve this question
RS Aggarwal, Class 10, chapter 3B, question no 16
6x+5y=7x+3y+1=2(x+6y−1)
6x+5y=7x+3y+1
⇒6x+5y−7x−3y=1
⇒−x+2y=1
⇒2y−x=1
Again 7x+3y+1=2(x+6y−1)
7x+3y+1=2x+12y−2
⇒7x+3y−2x−12y=−2−1
⇒5x−9y=−3
New set of equations is:
2y−x=1...(1)
5x−9y=−3...(2)
Using substitute method:
From (1),x=2y−1
Substitute the value of x in (2).
5(2y−1)−9y=−3
⇒10y−5−9y=−3
⇒y=−3+5
⇒y=2
And x=2y−1=2(2)−1=3
Answer: x=3,y=2