0 karansingh Asked: January 19, 20232023-01-19T00:13:52+05:30 2023-01-19T00:13:52+05:30In: CBSE . Solve for x and y: 0.4x-1.5y = 6.5, 0.3x-0.2y=0.9. 0 which method should we use to solve this. its from R.D sharma cbseclass 10linear equations Share Facebook 1 Answer Voted Oldest Recent [Deleted User] 2023-01-20T10:50:16+05:30Added an answer on January 20, 2023 at 10:50 am Given pair of linear equations is 0.4x – 1.5y = 6.5 …(i) And 0.3x + 0.2y = 0.9 …(ii) On multiplying Eq. (i) by 3 and Eq. (ii) by 4 to make the coefficients of x equal, we get the equation as 1.2x – 4.5y = 19.5 …(iii) 1.2x + 0.8y = 3.6 …(iv) On subtracting Eq. (iii) from Eq. (iv), we get 1.2x + 0.8y – 1.2x + 4.5y = 3.6 – 19.5 ⇒ 5.3y = – 15.9 y =-15.9/5.3 ⇒ y = – 3 On putting y = – 3 in Eq. (ii), we get 0.3x + 0.2y = 0.9 ⇒ 0.3x + 0.2( – 3) = 0.9 ⇒ 0.3x – 0.6 = 0.9 ⇒ 0.3x = 1.5 ⇒ x = 1.5/0.3 ⇒ x = 5 Hence, x = 5 and y = – 3 , -1 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Visual Text Save my name, email, and website in this browser for the next time I comment. Related Questions Speed of a boat in still water is 15 km/h. It goes 30 km upstream and returns back ... Find the values of k for which the pair of linear equations kx + 3y = k-2 and ... Solve graphically the system of linear equations 4x-5y +16=0 and 2x+y-6 = 0. Determine the vertices of the ... If the remainder on division of x3 + 2x2 + kx +3 by x – 3 is 21, ... Given that x – √5 is a factor of the polynomial x3 – 3√5x2 – 5x + 15√5, ...
Given pair of linear equations is
0.4x – 1.5y = 6.5 …(i)
And 0.3x + 0.2y = 0.9 …(ii)
On multiplying Eq. (i) by 3 and Eq. (ii) by 4 to make the coefficients of x equal,
we get the equation as
1.2x – 4.5y = 19.5 …(iii)
1.2x + 0.8y = 3.6 …(iv)
On subtracting Eq. (iii) from Eq. (iv), we get
1.2x + 0.8y – 1.2x + 4.5y = 3.6 – 19.5
⇒ 5.3y = – 15.9
y =-15.9/5.3
⇒ y = – 3
On putting y = – 3 in Eq. (ii), we get
0.3x + 0.2y = 0.9
⇒ 0.3x + 0.2( – 3) = 0.9
⇒ 0.3x – 0.6 = 0.9
⇒ 0.3x = 1.5
⇒ x = 1.5/0.3 ⇒ x = 5
Hence, x = 5 and y = – 3 ,