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Show that the diagonals of a square are equal and bisect each other at right angles. Q.4

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How i solve the question of class 9th ncert math of Quadrilaterals chapter of exercise 8.1 of question no 4 think it is very important question of class 9th give me the tricky way for solving this question  Show that the diagonals of a square are equal and bisect each other at right angles.

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  1. Ncert solutions class 9 chapter 8-3

    Let ABCD be a square and its diagonals AC and BD intersect each other at O.

    To show that,

    AC = BD

    AO = OC

    and ∠AOB = 90°

    Proof,

    In ΔABC and ΔBAD,

    AB = BA (Common)

    ∠ABC = ∠BAD = 90°

    BC = AD (Given)

    ΔABC ≅ ΔBAD [SAS congruency]

    Thus,

    AC = BD [CPCT]

    diagonals are equal.

    Now,

    In ΔAOB and ΔCOD,

    ∠BAO = ∠DCO (Alternate interior angles)

    ∠AOB = ∠COD (Vertically opposite)

    AB = CD (Given)

    , ΔAOB ≅ ΔCOD [AAS congruency]

    Thus,

    AO = CO [CPCT].

    , Diagonal bisect each other.

    Now,

    In ΔAOB and ΔCOB,

    OB = OB (Given)

    AO = CO (diagonals are bisected)

    AB = CB (Sides of the square)

    , ΔAOB ≅ ΔCOB [SSS congruency]

    also, ∠AOB = ∠COB

    ∠AOB+∠COB = 180° (Linear pair)

    Thus, ∠AOB = ∠COB = 90°

    , Diagonals bisect each other at right angles

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  2. Ncert solutions class 9 chapter 8-3

    Let ABCD be a square and its diagonals AC and BD intersect each other at O.

    To show that,

    AC = BD

    AO = OC

    and ∠AOB = 90°

    Proof,

    In ΔABC and ΔBAD,

    AB = BA (Common)

    ∠ABC = ∠BAD = 90°

    BC = AD (Given)

    ΔABC ≅ ΔBAD [SAS congruency]

    Thus,

    AC = BD [CPCT]

    diagonals are equal.

    Now,

    In ΔAOB and ΔCOD,

    ∠BAO = ∠DCO (Alternate interior angles)

    ∠AOB = ∠COD (Vertically opposite)

    AB = CD (Given)

    , ΔAOB ≅ ΔCOD [AAS congruency]

    Thus,

    AO = CO [CPCT].

    , Diagonal bisect each other.

    Now,

    In ΔAOB and ΔCOB,

    OB = OB (Given)

    AO = CO (diagonals are bisected)

    AB = CB (Sides of the square)

    , ΔAOB ≅ ΔCOB [SSS congruency]

    also, ∠AOB = ∠COB

    ∠AOB+∠COB = 180° (Linear pair)

    Thus, ∠AOB = ∠COB = 90°

    , Diagonals bisect each other at right angles

    • 0
  3. Ncert solutions class 9 chapter 8-3

    Let ABCD be a square and its diagonals AC and BD intersect each other at O.

    To show that,

    AC = BD

    AO = OC

    and ∠AOB = 90°

    Proof,

    In ΔABC and ΔBAD,

    AB = BA (Common)

    ∠ABC = ∠BAD = 90°

    BC = AD (Given)

    ΔABC ≅ ΔBAD [SAS congruency]

    Thus,

    AC = BD [CPCT]

    diagonals are equal.

    Now,

    In ΔAOB and ΔCOD,

    ∠BAO = ∠DCO (Alternate interior angles)

    ∠AOB = ∠COD (Vertically opposite)

    AB = CD (Given)

    , ΔAOB ≅ ΔCOD [AAS congruency]

    Thus,

    AO = CO [CPCT].

    , Diagonal bisect each other.

    Now,

    In ΔAOB and ΔCOB,

    OB = OB (Given)

    AO = CO (diagonals are bisected)

    AB = CB (Sides of the square)

    , ΔAOB ≅ ΔCOB [SSS congruency]

    also, ∠AOB = ∠COB

    ∠AOB+∠COB = 180° (Linear pair)

    Thus, ∠AOB = ∠COB = 90°

    , Diagonals bisect each other at right angles

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