One of the most important and exam oriented question from Chapter name- circles
Topic – Angle properties of circles
Chapter number- 15
It is given that AD is a diameter of a circle with centre O and AB is tangent at A.
C is a point on the circle such that DC produced intersects the tangent of B.
Also ∠ABC = 50°, now we have to find ∠AOC.
ICSE Avichal publication
Understanding ICSE Mathematics
Question 19
Solution:
Given AB is tangent to the circle at A and OA is radius, OA ⊥ AB
In ∆ABD
<DAB+<ABD+<ADB=180
90+50+<ADB=180
<ADB=40
<AOC=<OCD+<ODC=40+40=80